The Wichita Fall Shootout

36-hole two-man shamble tournament. Both players tee off each hole. For the second stroke on each hole, one of the two balls is selected. The ball selected is played out as it lies by the player to whom the ball belongs. The other player drops or places within one club-length (if through the green or in a hazard, the ball is dropped) or on the exact spot (if on the putting green), not nearer the hole, of the position of the ball selected (for the second stroke) and plays out the hole with that ball. The player whose ball is selected IS NOT REQUIRED to hit first, but his ball MUST NOT be moved or marked (unless on the putting green), if he does not hit first. The position of the ball may not be improved from the rough to fairway, from fringe to putting green or to outside of a hazard (including bunkers). The team’s score for the hole is the lowest number of strokes taken between the two balls in play (as in Four-Ball). If one player fails to complete a hole, there is no penalty.